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Ugo [173]
3 years ago
7

01 1 point If a customer spends more than $20, he receives a 10% discount on his total bill: What does a customer whose bill is

$80 /pay?​
Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

try 40%

Step-by-step explanation:

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ratelena [41]
The perimeter of an object is equal to its sides added up.  Because this is a triangle, it will have 3 equal sides.  Since the triangle has 3 equal sides, its perimeter will be equal to one of its side lengths * 3.  

Because the perimeter will be equal to one of its side lengths * 3, x is equal to one of the triangle's side lengths.
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Misha Larkins [42]
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2 years ago
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A power plant discharges water into a river. Regulators determine that as long as the mean temperature of the discharged water i
nlexa [21]

Answer:

(A) Type I error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is more than 150°F but in actual the mean temperature of the discharged water was 150°F.

(B) Type II error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is no more than 150°F but in actual the mean temperature of the discharged water was more than 150°F.

(C) An environmental group will consider the Type II error more serious.

Step-by-step explanation:

We are given that a power plant discharges water into a river. Regulators determine that as long as the mean temperature of the discharged water is no more than 150°F, there will be no negative effects on the river’s ecosystem.

We are also given with the following hypothesis;

Null Hypothesis, H_0 : \mu = 150°F

Alternate Hypothesis, H_a : \mu > 150°F

(A) <u><em>Type I error</em></u><em> states that Probability of rejecting null hypothesis given the fact that null hypothesis was true or in other words Probability of rejecting a true hypothesis.</em>

So, Type I error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is more than 150°F but in actual the mean temperature of the discharged water was 150°F.

(B) <u><em>Type II error </em></u><em>states that Probability of accepting null hypothesis given the fact that null hypothesis was false or in other words Probability of accepting a false hypothesis.</em>

So, Type II error in the context of this problem is chances of regulators believing that the mean temperature of the discharged water is no more than 150°F but in actual the mean temperature of the discharged water was more than 150°F.

(C) An environmental group will consider the Type II error more serious because by committing Type II error they believe that the mean temperature of the discharged water is no more than 150°F and they assume that there is no negative effects on the river’s ecosystem but in reality that the mean temperature of the discharged water was more than 150°F and it is producing negative effects on the river’s ecosystem.

8 0
3 years ago
What is the other polynomial send help please
posledela
In mathematics, a polynomial<span> is an expression consisting of variables (also called indeterminates) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. An example of a </span>polynomial<span> of a single indeterminate x is x</span>2<span> − 4x + 7.</span>
6 0
3 years ago
The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu
Kazeer [188]

Answer:

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

Step-by-step explanation:

The logistic differential equation is as follows:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

In this problem, we have that:

K = 1200, which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that \frac{dP}{dt} = 400 when P = 200. With this, we can find r, that is, the growth rate,

So

\frac{dP}{dt} = rP(1 - \frac{P}{K})

400 = 200r(1 - \frac{200}{1200})

166.67r = 400

r = 2.4

So the differential equation is:

\frac{dP}{dt} = rP(1 - \frac{P}{K})

\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})

3 0
3 years ago
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