Question

A parallelogram with the sides of 6 and 10 has a area of 30 square root of 2. Find the measure of each angle of the parallelogram.
Small angle-? Large angle-?

Answer 1

$a=10,b=6,A=30 \sqrt{2} \\ \\A=ah_a=ab\sin\theta \\30 \sqrt{2} =10\times6\times\sin\theta \\ \\ \sin\theta= \frac{ \sqrt{2} }{2} \\ \\ \theta=45^o \\ \theta_1=180^o -\theta=180^o-45^o=135^o$

Answer 2

Answer:

small angle- 45°

Step-by-step explanation:

I know this is correct bc I just had this question and this was the correct answer