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lesya [120]
2 years ago
14

HELP ME TIMED PLZZ !!!

Mathematics
2 answers:
zaharov [31]2 years ago
6 0

Answer:

There are 77 more third graders than second graders.

Step-by-step explanation:

415-338=x

x=77

mrs_skeptik [129]2 years ago
3 0

Answer:

the answer is 77

Step-by-step explanation:

415-338 = 77

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Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
3 years ago
I need help! ASAP!! please and thank you
Neko [114]

Answer: The walking path around it.

Step-by-step explanation:

Remember the Pythagorean's theorem, for a triangle rectangle with catheti A and B, and with hypotenuse H, we have:

A^2 + B^2 = H^2

or

H = √(A^2 + B^2)

Here, A + B is the total distance for the path, while the hypotenuse is the distance for the bridge

Here we can see that:

A = 1170 ft

B = 520 ft

Then:

H = √( (520 ft)^2 + (1170 ft)^2) = 1280.4 ft

Now, let's compute the costs.

For the bridge, we know that each foot costs $11, then for 1280.4 ft the cost is:

Cost of the bridge = (1280.4)*$11 = $14,084.4

And for the walking path, the cost is $6 per foot, then the total cost of the path is:

Cost of the path = (520 ft + 1170 ft)*$6 = $10,140

We know that the bridge is preferred if it is within the range of $1500 for the path's cost.

This range is:

($10,140 - $1,500, $10,140 + $1,500) = ($8,640, $11,640)

Here we can see that the cost of the bridge does not belong to this range, (is higher) so the option we should recommend is the walking path around.

8 0
3 years ago
Evaluate the expression.
Viktor [21]

3x(6^12/6^10)

3x(6^12-10)


3x(6^2)

3x(36)

108x


Answer is c

8 0
3 years ago
the length of a rectangle is 3 cm more than twice its width. Find the largest possible width if the perimeter is at most 66cm
Vanyuwa [196]
If you let the width be x, then the length will be 2x + 3. The perimeter P is twice the width plus twice the length, i.e., P = 2*x + 2*(2x + 3) = 2x + 4x + 6 = 6x + 6. So if the perimeter is 66 cm then 66 = 6x + 6 ---> 6x = 60 ---> x = 10 cm., and so if the perimeter is at most 66 cm., the width can be at most 10 cm..
6 0
2 years ago
Read 2 more answers
Arthur bought a life insurance policy at $10.98 per month for a 20 year term. What will he pay over 20 years for the premium?
mrs_skeptik [129]
D is the right answer
3 0
3 years ago
Read 2 more answers
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