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Andreas93 [3]
3 years ago
5

Which expression represents the algebraic phrase “the sum of negative three-eighths and four times x minus nine times z”?

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

(-3/8+4x)-9z            

C. Negative StartFraction 3 over 8 EndFraction + 4 x minus 9 z

Step-by-step explanation:

You might be interested in
Three pounds of fertilizer covers 900 feet.How many pound of fertilizer will cover 2,100 feet?
sveticcg [70]
To solve this problem, you can make a proportion:

3/900 = x/2100

In this case, the x represents the pounds that will be needed to cover 2,100 feet.

The first step is to cross multiply like this:

3 * 2100 = 900 * x

Now you can simply the equation.

6300 = 900x

Now you divide both sides by 900 to cancel it out.

7 = x

So, your answer is 7 pounds.
7 0
3 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

In y=\frac{7}{11}x when x=3, y≈1.90

We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


5 0
2 years ago
What is : 3 decreased by 100 ?
Murljashka [212]
3 decreased by 100 is -97. 3-100
5 0
3 years ago
Read 2 more answers
Is this Positive or Negative (3,528)(−17,438)(0)(−5,280)
Mekhanik [1.2K]

Answer:

Positive

Step-by-step explanation:

The negative and negative cancel each other out, and positive times positive is positive.

4 0
3 years ago
Read 2 more answers
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
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