The sum of two numbers
6x6=36
Twice first number
6x2=12
Minus the second
12-6=6
ANSWER
First number=6 Second number=6
we are given with a triangle with the sides 6 ft, 21 ft, 23 ft. although it follows the rule of triangles that state that no side of the triangle exceeds the sum of the lengths of two other sides, this does not follow Pythagorean theorem: 23^2-21^2 = 88 which is not equal to 6^2 or 36. This is not a right triangle, hence. Hope this helps!
Answer: It might be a no answer. I don't know which one. I'm so sorry if I'm wrong.
Answer:
62
Step-by-step explanation:
The enclosing rectangle is 24 units long and 12 units high. Its area is ...
(24 units)(12 units) = 288 square units
The white circles obviously cover more than half the area, so the only viable answer choice is 62.
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If you want to go to the trouble to actually figure it out, you can find the area of each circle using the area formula ...
A = πr² = (3.14)(6²) = 113.04
Then both circles have an area of 2×113.04 = 226.08, and the shaded area is the difference between that and the rectangle area:
shaded area = 288 -226.08 = 61.92 ≈ 62
Answer:
I had x to be 2
Step-by-step explanation:
a square has all it side to be equal
so 10x=6x+8
you will group like terms 10x-6x=8
4x=8 you divide both side by the coefficient of x which is four so X=2
