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2 years ago

Pls help me ASAP I have other homework to do and I don’t have time for this. It also detects if it’s right or wrong:(

Mathematics

2 answers:

ikadub [295]2 years ago

5 0

Answer:

$20

Step-by-step explanation:

you divide 40 by the two tickets and get $20.

lawyer [7]2 years ago

3 0

Answer:

$20

Step-by-step explanation:

2 into 40 = 20

3 into 60 = 20

4 into 80 = 20

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A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?

alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is $\frac{1}{13}$ .

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is $4\times 51!$ .

The probability that the last card dealt is an ace is

$P=\frac{4\times 51!}{52!}$

$P=\frac{4\times 51!}{52\times 51!}$

$P=\frac{4}{52}$

$P=\frac{1}{13}$

Therefore, the probability that the last card dealt is an ace is $\frac{1}{13}$ .

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