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solmaris [256]
3 years ago
7

Five cards are dealt form 52. a) How many different hands can be dealt? b) How many hands will contain 4 hearts? c) How many han

ds will contain no face cards? d) How many hands will contain only spades or only clubs? e) How many hands will contain only red cards? f) How many will contain no more than 2 face cards? g) How many will contain at least 2 hearts?
Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0
The answer will be d. hope that helped
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Thank you to anyone that helps
Margarita [4]

Answer:

10

Step-by-step explanation:

1 Subtract 150150 from both sides.

10x=200+5x-150

10x=200+5x−150

2 Simplify  200+5x-150200+5x−150  to  5x+505x+50.

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3 Subtract 5x5x from both sides.

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4 Simplify  10x-5x10x−5x  to  5x5x.

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5

50

​

6 Simplify  \frac{50}{5}

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  to  1010.

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x=10

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