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solmaris [256]
3 years ago
7

Five cards are dealt form 52. a) How many different hands can be dealt? b) How many hands will contain 4 hearts? c) How many han

ds will contain no face cards? d) How many hands will contain only spades or only clubs? e) How many hands will contain only red cards? f) How many will contain no more than 2 face cards? g) How many will contain at least 2 hearts?
Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0
The answer will be d. hope that helped
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Solve the inequality 8(x + 1) > 7(x + 2)
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Answer:

7(2 - x)

Step-by-step explanation:

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3 years ago
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1.Which equation gives the direct variation if y=8 when x=2?
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First one is y=4x and the second one is y=2x
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3 years ago
6.7 divided by 643.2 find the quotient
katrin2010 [14]

Answer:

1/96 or 0.01041666667

Step-by-step explanation:

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3 years ago
A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
Rewrite the equation 8x + 6x^2 -7=x^2 in standard form and identify a, b, and c.
Vladimir79 [104]

Answer:

5x^2+8x-7=0\\a=5\\b=8\\c=-7

Step-by-step explanation:

The standard form of a quadratic is ax^2+bx+c=0. You need to subtract the x^2 from the right to set the quadratic equal to 0. Then a,b, and c are equal to the values of the coefficients in front of the terms.

If this helped, a brainliest would be greatly appreciated!

6 0
3 years ago
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