3 years ago

2. What are the zeroes of P(x) = x3 – 6x2 – x +62

Mathematics

1 answer:

Inga [223]3 years ago

3 0

Step-by-step explanation:

if u mean (x^3 -6x^2 -x- 6) then the answer is C

(6,-1,1)

..................,..........

but if u mean P(x) = x3 – 6x2 – x +62

then the answer is None of the above

-2.724

4.361+1.9328i

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