2 years ago

Solve each equation

Mathematics

1 answer:

spayn [35]2 years ago

8 0

Answer:

Step-by-step explanation:

What equation??

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The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

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Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

2 years ago

Solve each equation​

Solve each equation