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Nonamiya [84]
3 years ago
15

I NEED HELP ASAP! PLEASEEE I WILL GIVE YOU EVERYTHING AND GOOD REVIEWS!!

Mathematics
1 answer:
Scrat [10]3 years ago
6 0

Answer:

no you will not be able to park the boat

Step-by-step explanation:

ok so now i need those reviews

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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
A high school has 44 players on the football team. The summary of the players' weights is given in the box plot. Approximately,
Marina CMI [18]

Answer:

Step-by-step explanation:

The missing image is attached below.

From the given information

The number of players is 44.

From the box plot;

The minimum weight = 154 pounds

The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.

The second quartile Q₂ = 213 which is 50% of the data below 213 pounds

The third quartile Q₃ = 253 which is 75% of the data below 253 pounds

The maximum weight = 268 pounds.

Here, the value of 213 is the middle value and which signifies the median.

The 50% of the data are located both on the left side and the right side of the median.

Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.

7 0
3 years ago
What is the percent or change-----$84 to 12%
zubka84 [21]
<span>$84 to 12%
</span>10.08
 is the answer
6 0
3 years ago
What is 0.3 as in the 3 repeating (i forgot what its called) as a simplified fraction?
NARA [144]
0.3333333333... = 1/3

You can just say 0.3 repeating to say 0.33333...
7 0
3 years ago
Please help!! ASAP thanks
Brut [27]

Answer:10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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