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3 years ago

6

Solve the equation for v

c{8}{av} +7" alt="y=\frac{8}{av} +7" align="absmiddle" class="latex-formula">

1 answer:

My name is Ann [436]3 years ago

3 0

Answer:

$v = \dfrac{8}{a(y - 7)}$

Step-by-step explanation:

$y = \dfrac{8}{av} + 7$

Subtract 7 from both sides.

$y - 7 = \dfrac{8}{av}$

Multiply both sides by v.

$v(y - 7) = \dfrac{8}{a}$

Multiply both sides by 1/(y - 7).

$v = \dfrac{8}{a(y - 7)}$

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National League Hockey play-off games go into overtime if the score is tied at the end of a game. Overtime lasts until one of th

Rzqust [24]

Answer:

0.07215 = 0.072 to 3 d.p.

Step-by-step explanation:

Central limit theorem explains that the sampling distribution obtained from this distribution will be approximately a normal distribution with

Mean = population mean

μₓ = μ = 9.8 minutes

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

σ = 12 minutes

n = sample size = 30

σₓ = (12/√30) = 2.191

Probability that a random sample of 30 overtime periods would have a (sample) mean length of more than 13 minutes

Required probability = P(x > 13)

Since we've established that this distribution of sample means approximates a normal distribution

We first standardize 13 minutes.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (13 - 9.8)/2.191 = 1.46

Required probability

P(x > 13) = P(z > 1.46)

We'll use data from the normal probability table for these probabilities

P(x > 13) = P(z > 1.46) = 1 - P(z ≤ 1.46)

= 1 - 0.92785 = 0.07215

Hope this Helps!!!

4 0

3 years ago

Write the expresion in simplest form<br> (-11/2x+30)-2(-11/4x-5/2)

qwelly [4]

The simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

<h3>How to simplify the expression?</h3>

The expression is given as:

(-11/2x+30)-2(-11/4x-5/2)

Expand the bracket

-11/2x + 30 + 11/2x + 5

Collect the like terms

11/2x -11/2x + 30 + 5

Evaluate the like terms

35

Hence, the simplified expression of (-11/2x+30)-2(-11/4x-5/2) is 35

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2 years ago

Step 6: Patterns can provide a clear understanding of mathematical relationships. This can be seen very clearly in the form of m

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Mathematical patterns are a sequence of repeated arrangements of numbers, shapes, colors, letters, etc.

Mathematical patterns are usually abstract.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence of non-zero numbers. The first number is the product of multiplying a previous number by a fixed, non-zero number, called the common ratio.

A Geometric sequence may look like: 2, 4, 8, 16, 32, 64, 128, ..., where the common ratio is 2.

<h3>What is a Fibonacci sequence?</h3>

A Fibonacci number starts with a zero, followed by a one, then by another one, and then by a series of steadily increasing numbers.

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5 0

2 years ago

How to solve this pythagoras theorem

My name is Ann [436]

Answer:

see explanation

Step-by-step explanation:

The hypotenuse is the longest side thus is (4x + 1)

The legs are 2x and (4x - 1)

Using Pythagoras' theorem, then

(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors

16x² + 8x + 1 = 4x² + 16x² - 8x + 1 , that is

16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )

- 4x² + 16x = 0 ( multiply through by - 1 )

4x² - 16x = 0 ← factor out 4x from each term

4x(x - 4) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x - 4 = 0 ⇒ x = 4

Now x > 0, thus x = 4

2x = 2(4) = 8

4x - 1 = 4(4) - 1 = 16 - 1 = 15

4x + 1 = 4(4) + 1 = 16 + 1 = 17

Thus

perimeter = 8 + 15 + 17 = 40 cm

3 0

3 years ago

Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh

a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let $\overline{x}$ and $\overline{y}$ be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume $\overline{x}$ having with mean $\mu_{1}$ and $\overline{y}$ having mean $\mu_{2}$

Also we have given the variance is constant

A)

We can test hypothesis as

$H0: \mu_{1} = \mu_{2}H1: \mu_{1} > \mu_{2}$

For this problem

Test statistic is

$T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}$

Where

$s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}$

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

3 0

3 years ago