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3 years ago

What is the value when x = 2? i need this asap!

Mathematics

2 answers:

Maru [420]3 years ago

8 0

Answer:

When x is 2 y equals 6.

Step-by-step explanation:

You go right on the graph two units then go up the y axis till the line intersects the lines. In this case the graphed point is (2,6)

labwork [276]3 years ago

6 0

Answer:

y=6!

Step-by-step explanation:

you can easily see it on the graph. on the x axis, 2 is equivalent to 6

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REBECA HAD 9/10 OF A YARDOF RIBBON. THEN SHE GAVE 7/20 OF A YARD OF FRIEND. HOW MUCH DOES SHE HAVE LEFT?

zzz [600]

Answer:

She has 11/20 yds left

Step-by-step explanation:

We take what she had and subtract what she gave away

9/10 - 7/20

We need to get a common denominator of 20

9/10 *2/2 - 7/20

18/20 - 7/20

11/20

She has 11/20 yds left

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3 years ago

Help algebra 2 please

iogann1982 [59]

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3 years ago

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3. Line A is represented by the equation, y = + 5 (a) Write in slope-intercept form the equation of a line that is parallel to L

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3 years ago

Suppose a box is to be constructed from a square piece of material of side length x by cutting out a 2-inch square from each cor

alexgriva [62]

Consider the attached figure. The central square is the "floor" of the box, and it is a (x-2)-by-(x-2) square.

The four rectangles of the side will be the "walls" of the box, and they are (x-2)-by-2 rectangles.

The volume is given by the base area multiplied by the height of the walls, so we have

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3 years ago

13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these

Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

$A \cap B \cap C = 1,000$ - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

$A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000$

It applies for I and III

$A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000$

And for II and III

$B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000$

The problem states that 10,000 people read the newspaper I, so:

$A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000$ where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

$B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000$

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

$C + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000$

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

$(A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000$

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

$(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000$

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

$100,000 - (A + B + C + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000$

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

$(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000$

10,000 people read only one morning paper and one evening paper.

3 0

3 years ago