Find the value of x. M (Round to the nearest degree as needed)

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

As we know:

$Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

5 0

3 years ago

What digit makes each number divisible by nine? _7,302

Alborosie

Answer:

Not completely sure but hopefully these will help.

Step-by-step explanation:

I'm kind of confused what you're asking for. If you could clarify that would be great. If you're trying to make it divisible by 9, you can either do 3, 6 or 9. If you want the first two digits: 2,5,8. Please clarify so I can help

8 0

4 years ago

A brace for a shelf has the shape of a right triangle. Its hypotenuse is 10 inches long and the two legs are equal in length. Ho

vagabundo [1.1K]

This is a classic example of a 45-45-90 triangle: it's a right triangle (one angle of 90) & two other sides of the same length, which means two angles of the same length (and 45 is the only number that will work). With a 45-45-90 triangle, the lengths of the legs are easy to determine:
45-45-90
1-1-sqrt2
Where the hypotenuse corresponds to sqrt2.
Now, your hypotenuse is 10.
To figure out what each leg is, divide 10/sqrt2 (because sqrt2/sqrt2 = 1, which is a leg length in the explanation above).
Problem: you can't divide by radicals. So, we'll have to rationalize the denominator:
(10•sqrt2)/(sqrt2•sqrt2)
This can be rewritten:
10sqrt2/sqrt(2•2)
=10sqrt2/sqrt4
=10sqrt2/2
=5sqrt2 Hope this helps!!

3 0

3 years ago

Please help please

jarptica [38.1K]

Answer:

1.) supplementary m<1+m<2=180 and m<2+m<3=180

2.) congruent, supplementary

Step-by-step explanation:

the answers are in this order above

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4 years ago

Scott had 3 equal stacks of baseball cards. He gave one stack to his brother Shawn.

Anuta_ua [19.1K]

90 cards in total and 30 in each stack

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4 years ago

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