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ludmilkaskok [199]
3 years ago
14

Given ƒ(x) = 8x + 25, find x when ƒ(x) = 9. A) −2 B) −1 C) 0 D) 2

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
8 0
A)-2
9=8x+25
-16=8x
x=-2
aniked [119]3 years ago
5 0
A) -2

9=8x+25
-16=8x
-2=x
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Find the exact value of x
Galina-37 [17]

Answer:

8.94 (Rounded would be 9)

Step-by-step explanation:

By using the Pythagorean Theorem formula,

A^2+B^2 = C^2

You have the hypotenuse (c)  = 12

and you have a leg (a) = 8

and you're trying to find another leg (b) = x

In order to find this, you'll have to change up the formula in order to find (B) instead of (C)

B^2 = C^2 - A^2

(B) = (12)^2 - (8)^2

(B) = 144 - 64

(B) = 80

Square root of 80

B = 8.9

5 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%28%20%20%7B81%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%29%5E%7B4%7D%20" id="TexFormula1" tit
Sveta_85 [38]
If you're asking how to simplify, then this is how you do it.

when a power meets another power but in brackets, then you have to multiply the powers. ¼ × 4 would be 1. i simplified 81 to 3⁴.

7 0
2 years ago
Write an equation to represent the following: Three consecutive integers add up to 11 more than the smallest.
mr Goodwill [35]

Answer:


Step-by-step explanation:

First we have to assume the smallest integer.

Let,

the smallest integer is  x

So, the other two integers are-

x+1  and   x+2

Now,  

the sum of these 3 integers is greater than smallest integer by  11

So, we get

x+(x+1)+(x+2) =x+11

This is the required equation.

5 0
3 years ago
what is the answer for this question and can tell me how to do this problem too. 791 + 11 &gt; 959 − 13
kompoz [17]

Answer:

The question is false

Step-by-step explanation:

4 0
3 years ago
For what values of a are the following expressions true?/a+5/=-5-a
katovenus [111]

Explanation:

The expression is given below as

|a+5|=-5-a

Concept:

We will apply the bsolute rule below

\begin{gathered} if|u|=a,a>0 \\ then,u=a,u=-a \end{gathered}

By applying the concept, we will have

\begin{gathered} \lvert a+5\rvert=-5-a \\ a+5=-5-a,a+5=5+a \\ a+a=-5-5,a-a=5-5 \\ 2a=-10,0=0 \\ \frac{2a}{2}=\frac{-10}{2},0=0 \\ a=-5,0=0 \end{gathered}

Hence,

The final answer is

a\leq-5

5 0
8 months ago
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