(lots of points) (dumbs answers will be reported)
1 answer:
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Answer:
The function is represented by
.
Step-by-step explanation:
Statement indicates that atmospheric pressure decreases exponentially when height above sea level is increased. This fact is represented by the following model:
(Eq. 1)
Where:
- Atmospheric pressure at sea level, measured in kilopascals.
-Atmospheric pressure decrease rate, dimensionless.
- Height above sea level, measured in kilometers.
- Current pressure, measured in kilopascals.
If we know that and
, the function
is represented by:
Answer:
(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780
(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.
Step-by-step explanation:
The random variable <em>Y</em> is defined as the number of consecutive time intervals in which the water supply remains below a critical value <em>y₀</em>.
The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em> = 0.409<em>.</em>
The probability mass function of a Geometric distribution is:
(a)
Compute the probability that a drought lasts exactly 3 intervals as follows:
Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.
Compute the probability that a drought lasts at most 3 intervals as follows:
P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)
Thus, the probability that a drought lasts at most 3 intervals is 0.8780.
(b)
Compute the mean of the random variable <em>Y</em> as follows:
Compute the standard deviation of the random variable <em>Y</em> as follows:
The probability that the length of a drought exceeds its mean value by at least one standard deviation is:
P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)
= P (Y ≥ 3.325)
= P (Y ≥ 3)
= 1 - P (Y < 3)
= 1 - P (X = 0) - P (X = 1) - P (X = 2)
Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.
The factors of the given expression are x , x - 2 and x - 4
![V(x)= x^{3}- 6x^{2}+8x \\ \\ V(x)=x( x^{2} -6x+8) \\ \\ V(x)=x( x^{2} -2x-4x+8) \\ \\ V(x)=x[x(x-2)-4(x-2)] \\ \\ V(x)=x(x-2)(x-4)](https://tex.z-dn.net/?f=V%28x%29%3D%20x%5E%7B3%7D-%20%206x%5E%7B2%7D%2B8x%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-6x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-2x-4x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%5Bx%28x-2%29-4%28x-2%29%5D%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28x-2%29%28x-4%29%20)
So the expression for height and length are x and x - 4
So the expression for height and length are x and x - 4