Answer:
- amplitude: 3
- period: π
- axis: y = 0
- range: [-3, +3]
Step-by-step explanation:
The amplitude is the multiplier of the sine function: 3.
The period is 2π divided by the coefficient of x: 2π/2 = π.
The equation of the axis is any added constant: y = 0.
The range is the axis value ± the amplitude value: from -3 to +3.
Answer:
0.4
Step-by-step explanation:
Given that:
P(debt) = P(D) = Probability of being in debt = 0.7
P(debt n Midwest) = P(Dn M) = probability of being in debt and lives in Midwest = 0.280
The probability that a randomly selected farmer lives in the Midwest given that he is in debt is?
P(M | D) = p(D n M) / p(D)
P(M | D) = 0.280 / 0.7
P(M | D) = 0.4
Check the picture below.
the triangle is an isosceles, so it has twin legs, and a base bottom.
the twin sides stem from the "vertex", and we know the vertex is 120°, and since the triangle is inscribed in a circle, because the circle is "circumscribing" it, then the base side of the triangle will be the diameter of it.
if we run a perpendicular line to the base from the vertex, we'll split the vertex in two 60° angles, as you see there, giving us a 30-60-90 triangle on each side.
so, anyhow, the rest is just a matter of using the 30-60-90 rule.
that's the diameter, and as you know, the radius is just the length of the base, or half the diameter.
Answer:

Step-by-step explanation:




