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Pavel [41]
3 years ago
13

Simplify: 3x – 4-5(6x + 7)

Mathematics
2 answers:
sdas [7]3 years ago
4 0

Answer:

− 27 x − 39

Step-by-step explanation:

I had this exact question before on my end of unit I passed it. If this helps please send thanks and feel free to give brainliest.

arsen [322]3 years ago
3 0

Answer:

Step-by-step explanation:

3x - 4 - 30x - 35

-27x - 39

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The measure of angle θ is 7 pi/6 . The measure of its reference angle is... °?, and sin θ is ...?
hjlf

Alright, let get started.

We have given the angle Ф as 7π/6.

And we are asked to find its reference angle (in dgrees)

So, we will first change 7π/6 from radian to degrees by multiplying 180/π

Ф = 7π/6 * 180/π

Ф = 7 * 180/6 = 210 degrees

Now, reference angle is the angle between X axis and the terminal side of given angle.

Please refer to the diagram attached.

The terminal side of angle 210 is lying in 3rd quadrant.

The angle between X axis and its terminal side is 210 - 180 = 30 degrees

Hence refernce agle of 210 degree or 7π/6 is 30 degrees. : Answer

We are also asked to find sin Ф

We could find it by using unit circle. sin 210 = - 1/2 Answer

Hope it will help :)

8 0
4 years ago
Does this triangle have a hypotenuse of 39 feet long
Whitepunk [10]

Answer:

Yes it does

Step-by-step explanation:

did it on edge

6 0
3 years ago
PLEASEE SOMEONE ANSWER ILL DO ANYTHING ANYTHING PLEAASEEE HELP ME this is myh 6th time posting this ;[
Sonbull [250]
What is the problem?
4 0
3 years ago
Question 20 not yet answered marked out of 1.00 not flaggedflag question question text luna created a trash can in the shape of
Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

1.

b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336

Then you can conclude that ∠B is obtuse (because \cos \angle B) and m∠B=110°.

2.

c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871.

Then you can conclude that ∠C is acute (because \cos \angle C>0) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

3 0
3 years ago
Find the angle between each of the following pair of straight line x-2y+3=0 and y=3x​
Serga [27]
-59.744
That’s when you solve for x and y in the equation x= 3/4 and y=-9/7
Tan inverse of y/x gives u -59.744
4 0
3 years ago
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