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AlekseyPX
3 years ago
13

If it takes four men three hours to dig two holes, how long does it take one man to dig three holes?

Mathematics
1 answer:
damaskus [11]3 years ago
8 0

Answer:

it will take one man 18 hours to dig the three holes

Step-by-step explanation:

To solve this problem, we can set up a simple relation as follows:

4 men dig two holes in 3hours

4 men will dig 1 hole in x hours.

2 holes => 3 hours

1 hole => x hours

x = (1 X 3)/2 = 1.5 hours

Therefore, 4 men will dig 1 hole in 1.5 hours.

From this, we can find how long it will take 1 man to dig 1 hole

if 4men dig a hole in 1.5 hours

1 man will dig 1 hole in x hours

4 X 1.5 = 6 hours

1 man will dig 1 hole in 6 hours

finally, if 1 man digs a hole in 6 hours, it will take the man 6 hours X 3 to dig 3 holes = 18hours

it will take one man 18 hours to dig the three holes

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Hannah earned $1536 in 8 years on an investment at a 4% annual simple interest rate. How much was Hannah’s investment? $4800 $30
Nonamiya [84]

Simple interest calculates interest on initial amount only. The investment by Hannah was : Option A: $4800

<h3>How to calculate simple interest amount if rate of interest is R% annually?</h3>

Suppose that the initial amount of investment is P

And the rate of simple interest is R% annually,

And the time of investment is T years.

Then, the amount of simple interest is calculated as:

I = \dfrac{P \times R \times T}{100}

For the given case, let the initial investment Hannah made was of $P

Then, the time of investment is T = 8 years, R% = 4%, and given that Hannah earned interest I = $1536

Putting values in the above formula, we get;

I = \dfrac{P \times R \times T}{100}\\\\1536 = \dfrac{P \times 8 \times 4}{100}\\\\P = \dfrac{153600}{32} = 4800

Thus,

The investment by Hannah was : Option A: $4800

Learn more about simple interest here:

brainly.com/question/5319581

5 0
3 years ago
a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v
Vika [28.1K]

Answer:

y = 34000(1-0.06) ^ t

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

y = P(1-n) ^ t

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

y = 34000(1-0.06) ^ t

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.

After 7.40 years it will be worth less than 21500

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3 years ago
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Slav-nsk [51]

Answer:

41 students

Step-by-step explanation:

20% of 205 is 41

7 0
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Answer:

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