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4 years ago

Find the unit rate. 6 2/5 revolutions in 2 2/3 seconds

1 answer:

6 0

The unit rate will be in revolutions per second. That means divide number of revolutions by number of seconds.

first convert from mixed fraction.
6 2/5 = 32/5 revolutions
2 2/3 = 8/3 seconds

32/5 ÷ 8/3
flip multiply
32/5 × 3/8 = 12/5 revolutions per second

12/5 = 2 2/5 revolutions per second

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What number is 60% of 85

ZanzabumX [31]

If you would to solve 60% of 85 is what number, you can calculate this using the following steps:

60% of 85 is x
60% * 85 = x
x = 60% * 85 = 60/100 * 85 = 51

Result: 60% of 85 is 51.

8 0

3 years ago

Read 2 more answers

Write the mixed number as a percent <br><br> 2 41/50

ehidna [41]

Answer:

∴ 2 $\frac{41}{50}$ = 282 %

Step-by-step explanation:

2 $\frac{41}{50}$

= [( 2 × 50) + 41] ÷ 50

= ( 100 + 41) ÷ 50

= $\frac{141}{50}$

=( $\frac{141 }{50}$ ) × $\frac{2}{2}$

= $\frac{282}{100}$

= 282 %

∴ 2 $\frac{41}{50}$ = 282 %

7 0

3 years ago

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How to simpfly fractions?<br> -Step by step <br> -Answer 15/36

Mumz [18]

Answer:

5/12

Step-by-step explanation:

15÷3/36 ÷3

the answer is 5/12

4 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST, SUPERB RATING, AND THANKS!

Vaselesa [24]

A line on this coordinate plane is horizontal when every input (x) has the same output y).

This function always gives the same output with no matter what input you put it in.

8 0

3 years ago

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

Sloan [31]

Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

4 0

3 years ago