6x+x-8=90 because right angle
7x=98 combine like terms
7x/7=98/7
X=14
m<1=6*14=84
m<2=14-8=6
Distribute: the way things are divided or spread out
Sentence: She studies the distribution of wildcats in the area.
Answer:
![A = \frac{h\sqrt{t^{2} - h^{2}}}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bh%5Csqrt%7Bt%5E%7B2%7D%20-%20h%5E%7B2%7D%7D%7D%7B2%7D)
Step-by-step explanation:
Right triangle:
height h, width w, hypotenuse h
Area is: ![A = \frac{h*w}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bh%2Aw%7D%7B2%7D)
Pytagoras theorem: ![h^{2} + w^{2} = t^{2}](https://tex.z-dn.net/?f=h%5E%7B2%7D%20%2B%20w%5E%7B2%7D%20%3D%20t%5E%7B2%7D)
In this question:
To find the area, in terms of h and t, we have to write w as a function of h and t. So
![h^{2} + w^{2} = t^{2}](https://tex.z-dn.net/?f=h%5E%7B2%7D%20%2B%20w%5E%7B2%7D%20%3D%20t%5E%7B2%7D)
![w^{2} = t^{2} - h^{2}](https://tex.z-dn.net/?f=w%5E%7B2%7D%20%3D%20t%5E%7B2%7D%20-%20h%5E%7B2%7D)
![w = \sqrt{t^{2} - h^{2}}](https://tex.z-dn.net/?f=w%20%3D%20%5Csqrt%7Bt%5E%7B2%7D%20-%20h%5E%7B2%7D%7D)
So the area is:
![A = \frac{h*w}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bh%2Aw%7D%7B2%7D)
![A = \frac{h\sqrt{t^{2} - h^{2}}}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Bh%5Csqrt%7Bt%5E%7B2%7D%20-%20h%5E%7B2%7D%7D%7D%7B2%7D)
Turn them both into mixed fractions and voila