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Alexus [3.1K]
3 years ago
5

Can somebody help me please thank you

Mathematics
2 answers:
vodomira [7]3 years ago
7 0
1 dreaming
2.climbing
3 recorded
Marianna [84]3 years ago
5 0

Answer:

1. WILL BE DREAMING

2. AM CLIMBING

3. WAS RECORDING

WILL BE PRESENTING

5. VERB = REHEARSING

THE ACTORS WILL BE REHEARSING

6. VERB= PRACTICING

THE BAND WILL BE PRACTICING A SONG

7. VERB= WRITING

KIM AND FABIO WILL BE WRITING THE PROGRAM

8. VERB=DESIGNING

MR.CLARK WILL BE DESIGNING A POSTER

Step-by-step explanation:

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Question 9: emathintruction can you guys help me? .....
stira [4]

Answer:

Choice #1) multiplied by 3

4 0
3 years ago
Find two positive numbers that differ by three and have a product of 14
garik1379 [7]
Create an equation: x*(x-3)=14
5.53112887 and 2.53112887
You can round the numbers and get 5.53 and 2.53
6 0
4 years ago
Brent decorated 1/6 of his sugar cookies with blue frosting 1/4 with yellow frosting and 3/8 with purple frosting which frosting
velikii [3]
If you look at the denominators, they all have a common number they can all multiply into: 24. If you multiply each number in the fraction so that the denominator equals 24, you get this:
1/6 x 4 = 4/24
1/4 x 6 = 6/24
3/8 x 3 = 6/24

Therefore, blue frosting (1/6) is used the least.

Hope this helps:
3 0
2 years ago
8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.
loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

^8C_4\times ^9C_5\times^9C_2\times^7C_3

=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0
3 years ago
Solve the inequality. 2 divided by 5 is greater than or equal to x minus the quantity 4 divided by 5 end of quantity.
In-s [12.5K]
2/5 ≥ x - (4/5). add 4/5 to each side
6/5 ≥ x
7 0
3 years ago
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