Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Answer:
1st pic:
Felix
mean: 11.31
median: 9
mode: none
range: 26
Tyler
mean: 56.57
median; 68
mode: none
range: 92
2nd pic:
The first histogram has a large amount of cheaper books and doesn't have any books that are above $29.99. This histogram sells cheaper books. The second histogram sells a more even distribution of books by cost. There are no bins that are significantly higher than the rest. This second histogram sells more expensive books.
3rd pic:
The first set of data shows that the difference in the prices is very small while the second set of data shows a larger variety of prices. The first set represents its prices in equally divided groups making it easier to read and determine than the second set of data.
Step-by-step explanation:
She bought 6 books in all because if you divide the whole number of all the books in all which is $32 divide that by 4 so..
32 ÷4=8
so thats just the 4 books then she buys 16 more dollars worth that which you then multiply 4 times 8 which give you 16 so you then add the 4 books to the other 2 books spent on the next day
ANSWER: 6 BOOKS IN ALL
Answer:
97290
Step-by-step explanation:
47 different people can win first
47
Now there are only 46 people left
46 different people can win second
46
45 different people can win third
47*46*45
97290
