The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)
Thus we have two foci
(0,3) and (0,-3)
Answer:
nothing is showing up
Step-by-step explanation:
Answer:23.06
Step-by-step explanation:
subtract 85.6 from 62.54 and that should shoot out your answer
Let the numbers be x = 5x+18
3(5x+18) + 4x= 16
15x+ 54+ 4x= 16
19x = 16-54
X=-38/19
X= -2
5x+18= 5 × -2+18 = 8
