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Ivahew [28]
3 years ago
11

What is an example of a recent development in technology

Computers and Technology
2 answers:
givi [52]3 years ago
8 0

Artificial Intelligence (AI) and Machine Learning. ...

Robotic Process Automation (RPA) ...

Edge Computing. ...

Quantum Computing. ...

Virtual Reality and Augmented Reality. ...

Blockchain. ...

Internet of Things (IoT) ...

5G.

Nezavi [6.7K]3 years ago
4 0

Answer:

every day new things are made and different.

You might be interested in
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static
yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}

7 0
3 years ago
Homework 8 Matlab Write a function called fibonacciMatrix. It should have three inputs, col1, col2, and n. col1 and col2 are ver
Amiraneli [1.4K]

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>end</em>

<em>end</em>

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>elseif n<1</em>

<em>    v = 0;</em>

<em>end</em>

<em>function [n] = abcd(x)</em>

<em>if (x == 1 || x==0)</em>

<em>    n = x; </em>

<em>    return</em>

<em>else</em>

<em>    n = abcd(x-1) + abcd(x-2);</em>

<em>end</em>

<em>end</em>

<em>fibonacci = [0 1];</em>

<em>for i = 1:n-2</em>

<em>    fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];</em>

<em>end</em>

<em>>> myfib(8)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13</em>

<em>>> myfib(10)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13   21   34</em>

See more about python at  brainly.com/question/18502436

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