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Mekhanik [1.2K]
3 years ago
10

Please answer me in Assignment - Algorithms

Computers and Technology
1 answer:
uysha [10]3 years ago
4 0

ajahjahakahkajakakhabavfwhasp

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Assume that getPlayer2Move works as specified, regardless of what you wrote in part (a) . You must use getPlayer1Move and getPla
kakasveta [241]

Answer:

(1)

public int getPlayer2Move(int round)

{

  int result = 0;

 

  //If round is divided by 3

  if(round%3 == 0) {

      result= 3;

  }

  //if round is not divided by 3 and is divided by 2

  else if(round%3 != 0 && round%2 == 0) {

      result = 2;

  }

  //if round is not divided by 3 or 2

  else {

      result = 1;

  }

 

  return result;

}

(2)

public void playGame()

{

 

  //Initializing player 1 coins

  int player1Coins = startingCoins;

 

  //Initializing player 2 coins

  int player2Coins = startingCoins;

 

 

  for ( int round = 1 ; round <= maxRounds ; round++) {

     

      //if the player 1 or player 2 coins are less than 3

      if(player1Coins < 3 || player2Coins < 3) {

          break;

      }

     

      //The number of coins player 1 spends

      int player1Spends = getPlayer1Move();

     

      //The number of coins player 2 spends

      int player2Spends = getPlayer2Move(round);

     

      //Remaining coins of player 1

      player1Coins -= player1Spends;

     

      //Remaining coins of player 2

      player2Coins -= player2Spends;

     

      //If player 2 spends the same number of coins as player 2 spends

      if ( player1Spends == player2Spends) {

          player2Coins += 1;

          continue;

      }

     

      //positive difference between the number of coins spent by the two players

      int difference = Math.abs(player1Spends - player2Spends) ;

     

      //if difference is 1

      if( difference == 1) {

          player2Coins += 1;

          continue;

      }

     

      //If difference is 2

      if(difference == 2) {

          player1Coins += 2;

          continue;

      }

     

     

  }

 

  // At the end of the game

  //If player 1 coins is equal to player two coins

  if(player1Coins == player2Coins) {

      System.out.println("tie game");

  }

  //If player 1 coins are greater than player 2 coins

  else if(player1Coins > player2Coins) {

      System.out.println("player 1 wins");

  }

  //If player 2 coins is grater than player 2 coins

  else if(player1Coins < player2Coins) {

      System.out.println("player 2 wins");

  }

}

3 0
3 years ago
Write a Python function that join the two string and print it ​
liubo4ka [24]

Answer:

string1 = "this is string 1"

string2 = " this is string 2"

print(string1 + string2)

Explanation:

the string1 variable is assigned with a string value(aka. str)

string2 is also a variable assigned with a slightly different string value

the 3rd line then prints string 1 and 2 to the console.

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Drag each tile to the correct box.
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I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho
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Which of these is not one of the main parts of an email?
pav-90 [236]
The header is not a main part of the email. 
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3 years ago
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Keith has to carry out a photo shoot to capture images of the ocean during the monsoons. What is a recommended practice when sho
Semmy [17]

Answer:

Answer is A: place absorbent chemical packets in the camera cover

Explanation:

Keith is required to carry adequate gear while going for a shoot. And in this case, he should carry anything that will protect his camera from the ocean and rainwater. By anything, I mean anything that Keith will use to stay dry. Using an air conditioner would be the worst idea. An air conditioner might blow the air towards your camera. Placing the camera in its case will ensure that it is dry and Keith will keep on shooting. Placing absorbent chemical packets in the camera cover will ensure that any water droplets that might fall on the cover of the camera will be absorbed. The point here is to keep dry.

6 0
3 years ago
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