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laiz [17]
3 years ago
9

1) why is software engineering considered engineering and not manufacturing?

Computers and Technology
1 answer:
Setler79 [48]3 years ago
7 0

Answer:

Software engineering is the process of designing and testing various analytical data and are used to analyzing the needs of user for development.

Engineering basically refers to the designing and planning on the other hand, manufacturing refers to the process that involved raw material and machines.

Software engineering basically apply their all the computer skills for designing an efficient software and it does not use any type pf machines and raw material. Therefore, software engineering consider engineering and not manufacturing.  

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Alborosie
Google drive or Dropbox. Services like that.
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If you wouldn't want someone to photograph you doing something, don't photograph someone else in that situation either. True Fal
Sunny_sXe [5.5K]

In the United States, it's illegal for a photographer to use someone's likeness ... Model release forms contain conditions on working with people, and in some ... You'll need this release form if you want to publish photos of another person's ... If you don't want to take any legal risks, then use a photo release form to be safe.

4 0
3 years ago
Write a function SwapArrayEnds() that swaps the first and last elements of the function's array parameter. Ex: sortArray = {10,
ludmilkaskok [199]

Answer:

Replace /* Your solution goes here*/ with the following

<em>void SwapArrayEnds(int sortArray [], int lent){ </em>

<em>    int temp = sortArray[0]; </em>

<em>    sortArray[0] = sortArray[lent-1]; </em>

<em>    sortArray[lent-1] = temp; </em>

<em>} </em>

<em />

Explanation:

This defines the function SwapArrayEnds with two parameter (the array and the array length)

<em>void SwapArrayEnds(int sortArray [], int lent){ </em>

This declares an integer variable "temp" and initializes it with the first element of the array

<em>    int temp = sortArray[0]; </em>

The next two lines swap the last element with the first

<em>    sortArray[0] = sortArray[lent-1]; </em>

<em>    sortArray[lent-1] = temp; </em>

<em>} </em>

<em />

<em>See attachment for full program</em>

Download cpp
3 0
3 years ago
Let S be an NP-complete problem and Q and R be two other problems not known to be in NP. Q is polynomial time reducible to S and
levacccp [35]

Answer:

B. R is NP Hard

Explanation:

Given:

S is an NP complete problem

Q is not known to be in NP

R is not known to be in NP

Q is polynomial times reducible to S

S is polynomial times reducible to R  

Solution:

NP complete problem has to be in both NP and NP-hard. A problem is NP hard if all problems in NP are polynomial time reducible to it.

Option B is correct because as given in the question S is an NP complete problem and S is polynomial times reducible to R.

Option A is not correct because R is not known to be in NP

Option C is not correct because Q is also not known to be in NP

Option D is not correct because Q because no NP-complete problem is polynomial time reducible to Q.

5 0
3 years ago
Writing down your main ideas, subpoints, and supporting material, then using geometric shapes and arrows to indicate logical rel
horsena [70]

The process that involves writing down your main ideas, subpoints, and supporting material, then using geometric shapes is mapping.

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Learn more about mapping at:

brainly.com/question/25168859

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