Here is for solving for x
Answer:
Statement 4 in true.
Step-by-step explanation:
1. f(-2)=(-3*(-2)+2)^2+(-2)=(6+2)^2+(-2)=8^2-2=62, FALSE
2. f(-5)=(-3*(-5)+2)^2+(-5)=(15+2)^2+(-5)=17^2+(-5)=289-5=284, FALSE
3. f(3)=(-3*3+2)^2+3=(-9+2)^2+3=(-7)^2+3=49+3=52, FALSE
4. f(5)=(-3*5+2)^2+5=(-15+2)^2+5=(-13)^2+5=169+5=174, TRUE
We presume you want to find values of x that make this true.
Subtract the right side and factor:

Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.
To solve 2x-5=0, you can add 5 then divide by 2:
... 2x -5 = 0
... 2x = 5
... x = 5/2
The answer is 2
One Solution
6s-10= 1s
-6s -6s
_________
-10=-5s
Divide -10 and -5
You'll get 2
X=1