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rosijanka [135]
3 years ago
13

Find x

smiddle" class="latex-formula">
Mathematics
1 answer:
MArishka [77]3 years ago
5 0
I will assume the question is log (8x) = 4/3

This means, "The exponent we put on 10 to get 8x is 4/3"

10^(4/3) = 8x

x = [10^(4/3)]/8

x = 2.69


log (8*2.69) = 4/3 ?
log (21.52) = 4/3
1.33 = 4/3
1.33 = 1.33
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I had this question in my class and got it right with answer A :')

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Anon25 [30]

Answer:

1). t ≥ -\frac{3}{2}

2). k ≥ \frac{16}{3}

3). y < -\frac{1}{2}

4). b > \frac{250}{9}

5). w ≤ 0

Step-by-step explanation:

1). 14(\frac{1}{2}-t)\leq 28

   \frac{14}{14}(\frac{1}{2}-t)\leq \frac{28}{14}

   \frac{1}{2}-t\leq 2

   -t\leq 2-\frac{1}{2}

   -t\leq \frac{3}{2}

   t ≥ -\frac{3}{2}

2). 15k + 11 ≤ 18k - 5

   15k - 18k ≤ -5 - 11

   -3k ≤ - 16

   3k ≥ 16

     k ≥ \frac{16}{3}

3). 44y > 11 + 88y - 22y

    44y > 11 + 66y

    44y - 66y > 11

    -22y > 11

    22y < -11

    \frac{22y}{22}

    y < -\frac{1}{2}

4). \frac{7}{9}(b - 27) > \frac{49}{81}

    \frac{7}{9}(b - 27)\times \frac{9}{7} > \frac{49}{81}\times \frac{9}{7}

     (b - 27) > \frac{7}{9}

     b > \frac{7}{9}+27

    b > \frac{250}{9}

5). 11w - 8w ≥ 14w

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    -11w ≥ 0

    w ≤ 0

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