1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
10

Selection Sort List the resulting array after each iteration of the outer loop of the selection sort algorithm. Indicate the num

ber of character-to-character comparisons made for each iteration (line 07 of the Selection Sort algorithm at the end of the assignment). Sort the following array of characters (sort into alphabetical order): CQS A XBT Selection Sort 01 public static void selectionSort (int[] a) { 02 03 int n = a.length; for (int i = 0 ; i 0; j--) { if ( a[j-1] > a[j] ) { exchange(a, j-1, j); } else break; 10 } 12 private static void exchange (int[] a, int i, int j) { 13 // exchange the value at index i with the value at index j int temp = a[i]; a[i] = a[j]; a[j] = temp; 17 }
Computers and Technology
1 answer:
Lady bird [3.3K]3 years ago
4 0

Solution :

Initial array = $\text{C,Q,S,A,X,B,T}$

$n= 7$(length of the array)

$\text{1st}$ Iteration:

i = 1

  j = 1

  $\text{a[j-1]}$ = C

  a[j] = Q

  since $\text{a[j-1]}$ < a[j] , break from inner loop

 

Number of comparisons in 1st Iteration = 1

After 1st Iteration:

Array : C,Q,S,A,X,B,T

2nd Iteration:

i = 2

  j = 2

  a[j-1] = Q

  a[j] = S

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 2nd Iteration = 1

After 2nd Iteration:

Array : C,Q,S,A,X,B,T

3rd Iteration:

i = 3

  j = 3

  a[j-1] = S

  a[j] = A

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : C,Q,A,S,X,B,T

 

  j = 2

  a[j-1] = Q

  a[j] = A

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : C,A,Q,S,X,B,T

 

  j = 1

  a[j-1] = C

  a[j] = A

  since a[j-1] > a[j], exchange a[0] with a[1]

  Array : A,C,Q,S,X,B,T

 

  j = 0, break from inner loop

Number of comparisons in 3rd Iteration = 3

After 3rd Iteration:

Array : A,C,Q,S,X,B,T

4th Iteration:

i = 4

  j = 4

  a[j-1] = S

  a[j] = X

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 4th Iteration = 1

After 4th Iteration:

Array : A,C,Q,S,X,B,T

5th Iteration:

i = 5

  j = 5

  a[j-1] = X

  a[j] = B

  since a[j-1] > a[j], exchange a[4] with a[5]

  Array : A,C,Q,S,B,X,T

 

  j = 4

  a[j-1] = S

  a[j] = B

  since a[j-1] > a[j], exchange a[3] with a[4]

  Array : A,C,Q,B,S,X,T

 

  j = 3

  a[j-1] = Q

  a[j] = B

  since a[j-1] > a[j], exchange a[2] with a[3]

  Array : A,C,B,Q,S,X,T

 

  j = 2

  a[j-1] = C

  a[j] = B

  since a[j-1] > a[j], exchange a[1] with a[2]

  Array : A,B,C,Q,S,X,T

 

  j = 1

  a[j-1] = A

  a[j] = B

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 5th Iteration = 5

After 5th Iteration:

Array : A,B,C,Q,S,X,T

6th Iteration:

i = 6

  j = 6

  a[j-1] = X

  a[j] = T

  since a[j-1] > a[j], exchange a[5] with a[6]

  Array : A,B,C,Q,S,T,X

 

  j = 5

  a[j-1] = S

  a[j] = T

  since a[j-1] < a[j], break from inner loop

 

Number of comparisons in 6th Iteration = 2

After 6th Iteration:

Array : A,B,C,Q,S,T,X

Sorted Array : A B C Q S T X  

You might be interested in
Consider a pipelined processor with just one level of cache. assume that in the absence of memory delays, the baseline cpi of th
babunello [35]

Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.

8 0
2 years ago
Joe, a user, wants his desktop RAID configured to allow the fastest speed and the most storage capacity. His desktop has three h
kirill115 [55]

Answer:

A. 0

Explanation:

The technician should configure the RAID 0 for Joe.

RAID 0 also referred to as the striped volume or stripe set is configured to allow the fastest speed and the most storage capacity by splitting data evenly across multiple (at least two) disks, without redundancy and parity information.

Also, RAID 0 isn't fault tolerant, as failure of one drive will cause the entire array to fail thereby causing total data loss.

7 0
3 years ago
CODING TIME
Fynjy0 [20]

Answer:

food_list = ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

one_more = ['meat']

extend_list = food_list + one_more

print(extend_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'meat']

food_list.append('milk')

print(food_list)

Output : ['rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea', 'milk']

food_list.insert(0, 'cake')

print(food_list)

Output : ['cake', 'rice', 'beans','yam', 'bread', 'pasta', 'cocoa','tea']

flowers = ['rose', 'hibiscus', 'lily']

flowers.remove('rose')

print(flowers)

Output : ['hibiscus', 'lily']

To remove rose using pop()

flowers.pop(0)

Explanation:

The + operator and append method adds elements to the end of an existing list item.

The insert method adds element at the specified index

Remove method deletes element by stating the name of the element to be deleted while pop deletes element using the index value of the element.

7 0
2 years ago
You step out of your office and miss a telephone call. when you sit at your desk you notice that the voicemail light is blinking
Sauron [17]
The answer is <span>Unified Communications.  </span><span>You step out of your office and miss a telephone call. when you sit at your desk you notice that the voicemail light is blinking on your phone, you have a new email, and you have a transcribed instant message on your computer screen in the form of an instant message. your organization has most likely adopted Unified Communications type of technology.  </span>
6 0
3 years ago
What is Deep learning
vodomira [7]

Answer:

Deep learning is an AI function that mimics the workings of the human brain in processing data for use in detecting objects, recognizing speech, translating languages, and making decisions. Deep learning AI is able to learn without human supervision, drawing from data that is both unstructured and unlabeled.

3 0
3 years ago
Other questions:
  • Who should get the copyright credit for a piece of computer art: the CPU, the software, or the programmer? Explain your reasonin
    7·1 answer
  • ICT excel data homework
    10·1 answer
  • Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in th
    11·1 answer
  • A Windows application which demands a lot of raw processing power to execute repetitive complex calculations is a good candidate
    5·1 answer
  • Where (what memory location) is the data read from for the following code:
    12·1 answer
  • Write a script that will read from a file x and y data points in thefollowing format:
    9·1 answer
  • In the Mouse Properties window, you can?
    8·1 answer
  • What is a Software that interprets commands drom the keyboard and mouse
    13·1 answer
  • Ns.office.com/Pages/ResponsePage.aspx?id=bd8
    9·2 answers
  • Assume in the for loop header, the range function has the three arguments: range (1, 10, 3), if you were to print out the value
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!