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Ksenya-84 [330]
3 years ago
12

There is always this thing that comes out and I can't answer one's question. How do I undo this?

Computers and Technology
2 answers:
Y_Kistochka [10]3 years ago
8 0
You should enter your email address
Keith_Richards [23]3 years ago
3 0

Answer:

translate the page by clicking the top right symbol in search to translate page

Explanation:

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100 POINTS!!!!
Alisiya [41]

Answer:

☆<em>intellectual property</em>☆

<u>intangible </u><u>a</u><u>s</u><u>s</u><u>e</u><u>t</u><u>s</u><u> </u><u> that result from intellectual</u><u> </u><u>p</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>.</u>

<u>☆</u><u>I</u><u>n</u><u>t</u><u>a</u><u>n</u><u>g</u><u>i</u><u>b</u><u>l</u><u>e</u><u>☆</u><u>;</u>

<u>s</u><u>o</u><u>m</u><u>e</u><u>t</u><u>h</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>c</u><u>a</u><u>n</u><u>n</u><u>o</u><u>t</u><u> </u><u>b</u><u>e</u><u> </u><u>t</u><u>o</u><u>u</u><u>c</u><u>h</u><u>e</u><u>d</u><u>.</u>

<em>P</em><em>l</em><em>e</em><em>a</em><em>s</em><em>e</em><em> </em><em>M</em><em>a</em><em>r</em><em>k</em><em>☆</em>

<em>A</em><em>r</em><em>i</em><em>a</em><em>♡</em>

5 0
3 years ago
A positive return on investment for higher education.
lesya692 [45]

Answer: is when your earnings potential is higher than the cost of your education

Explanation:

A positive return on investment on a particular thing occurs when the benefit derived is more than the cost that was incurred while in a scenario whereby the cost is more than the benefit, a negative return on investment took place.

In this case, a positive return on investment for higher education occurs when your earnings potential is higher than the cost of your education.

5 0
3 years ago
A host is on the 192.168.146.0 network that has a subnet mask of 255.255.255.0. The binary value of the host portion is 11010101
QveST [7]

Answer:

213

Explanation:

The given parameters are;

The network on which the host is on = 192.168.146.0

The subnet mast = 255.255.255.0

The binary value of the host portion = 11010101

To convert the binary value to decimal value, we proceed by multiplying each of the digits of the binary value by the corresponding power of 2, from the left to right, starting from a power of 0, and sum the result, as follows;

(11010101)₂ = (1×2⁷ + 1×2⁶ + 0×2⁵ + 1×2⁴ + 0×2³ + 1×2² + 0×2¹ + 1×2⁰)₁₀

1×2⁷+1×2⁶+0×2⁵+1×2⁴+0×2³+1×2²+0×2¹+1×2⁰= 128+64+0+16+4+1 = 213

∴ (11010101)₂ = (213)₁₀

The decimal value of 11010101 is 213.

8 0
3 years ago
Write a program that will input the names, ages and weights of three siblings and display the lightest followed by the youngest
jekas [21]

Answer:

Here is the JAVA program:

Sibling.java class:

import java.util.Scanner;  //to accept input from user

public class Sibling {  //class name

//private data members of class

   private String name;  // String type variable to hold the name of sibling

   private int age;  // int type variable to hold the age of sibling

   private int weight;  // int type variable to hold the weight of sibling

   public Sibling() {}     //constructor of class Sibling

   public Sibling (String n, int a, int w)  {  //parameterized constructor

       name = n;  // refers to name field

       age = a;  // refers to age field

       weight = w;    }   // refers to weight field

   public String getName ()    {   //accessor method to get the current name of sibling

       return name;    }   //returns the name field of the sibling

   public int getAge ()    {   //accessor method to get the current age of sibling

       return age;    }   //returns the age field of the sibling

   public int getWeight (){ //accessor method to get the current weight of sibling

    return weight;    } //returns the weight field of the sibling

   public void getInput() {    //to take input name,age and weight from user

 Scanner input = new Scanner(System.in);  //Scanner class object

 System.out.print("Enter the name:  ");  //prompts user to enter the name of sibling

 name = input.nextLine();  //scans and reads the input name from user

 System.out.print("Enter the age:  ");  //prompts user to enter the age of sibling

 age = input.nextInt();   //scans and reads the age from user

 System.out.print("Enter the weight:  ");  //prompts user to enter the weight of sibling

 weight = input.nextInt(); } }   //scans and reads the input weight from user

Explanation:

Here is the TestSibling class that contains main method:

public class TestSibling {   //class name

public static void main (String[] args) {   //main method

String name;  // to hold name of sibling

int age, weight;   // to hold age and weight of sibling

Sibling sib1, sib2, sib3;   // objects of Sibling class

sib1 = new Sibling ();  // creates object of class Sibling for sibling 1 and calls constructor

sib1.getInput();   // calls getInput method using sib1 object to get the name, age and weight of sibling 1

sib2 = new Sibling ();  // creates object of class Sibling for sibling 2 and calls constructor

sib2.getInput();   //calls getInput method using sib2 object to get the name, age and weight of sibling 2

sib3 = new Sibling ();  //creates object of class Sibling for sibling 3 and calls constructor

sib3.getInput();   //calls getInput method using sib3 object to get the name, age and weight of sibling 3

Sibling youngest=null, lightest=null;    //holds the youngest age and lightest weight of siblings

if (sib1.getAge( )<= sib2.getAge( ) && sib1.getAge( ) <= sib3.getAge( ) )   /*if condition checks if age of sibling 1 is less than or equals to that of sibling 2 and sibling 3,  using object of each sibling and getAge method to access age. the logical operator && AND is used so that if condition evaluates to true if sib1 is younger than both sib2 and sib3 */

{ youngest=sib1;}   //if the above condition is true then sets sib1 as youngest

else if (sib2.getAge( ) <= sib1.getAge( ) && sib2.getAge( ) <= sib3.getAge( ) )   // else if condition checks if age of sibling 2 is less than or equals to that of sibling 1 and sibling 3

{youngest=sib2;}   // if above condition is true then sets sib2 as the youngest

else   //if none of the above condition is true then this means that the third has the lowest age

{            youngest=sib3;    }    //sets sib3 as the youngest

if (sib1.getWeight( ) <= sib2.getWeight( ) && sib1.getWeight( ) <= sib3.getWeight( ) )   //if condition checks if weight of sibling 1 is less than or equals to that of sibling 2 and sibling 3,  using object of each sibling and getAge method to access weight of each sibling

          { lightest=sib1; }   //if the above condition is true then sets sib1 as having the lightest weight

else if (sib2.getWeight( ) <= sib1.getWeight( ) && sib2.getWeight( ) <= sib3.getWeight( ) )  // else if condition checks if weight of sibling 2 is less than or equals to that of sibling 1 and sibling 3

{lightest=sib2; }  //if the above condition is true then sets sib2 as the lightest

else  //if none of the above condition is true then this means that the third has the lightest weight

{ lightest=sib3;   }  //sets sib3 as the lightest

System.out.println("The lightest sibling: " + lightest.getName() +" " + lightest.getAge()+" "+ lightest.getWeight());  } } //calls the getName() getAge() and getWeight() method using object lightest to print the lightest of the siblings

System.out.println("The youngest sibling: " + youngest.getName() +" " + youngest.getAge()+" "+ youngest.getWeight());  //calls the getName() getAge() and getWeight() method using object youngest to print the youngest of the siblings

The screenshot of the output is attached.

4 0
3 years ago
Demonstrate your grasp of the Unix file system by constructing a directory structure as follows: In your home ( ~ ) directory, c
s2008m [1.1K]

Answer:

The steps to follow in executing the command are listed in the Explanation section

Explanation:

Open the terminal using Ctrl + Alt + T

To go to home directory, type: cd ~ OR just cd

To create a directory named UnixCourse, type: mkdir UnixCourse

To change directory to UnixCourse, type: cd UnixCourse

To create a fileAsst directory, type: mkdir fileAsst

To change directory into fileAsst, type: cd fileAsst

To create TweedleDee directory, type: mkdir TweedleDee

To create TweedleDum direectory, type: mkdir TweedleDum

To view the directory, type: ls

To copy from one directory to another:

cp ~/cs252/Assignments/fileAsst/hatter.txt  ~/UnixCourse/fileAsst/TweedleDee

To change to TweedleDee directory and list to view:

cd TweedleDee

ls

cd .. (this is to go back to the fileAsst directory)

To copy from one directory to another:

cp ~/cs252/Assignments/fileAsst/dormouse.txt  ~/UnixCourse/fileAsst/TweedleDum

To change to TweedleDum directory and list to view:

cd TweedleDum

ls

cd .. (this is to go back to the fileAsst directory)

The command below is executed as required:

~/cs252/bin/fileAsst-1

We check the directory for new file:

ls (to display entire file/folder)

then move the new file to TweedleDee directory

mv ~/UnixCourse/fileAsst/'name of file' ~/UnixCourse/fileAsst/TweedleDee

we then rename the file to rabbit.dat

mv ~/UnixCourse/fileAsst/TweedleDee/'name of file' ~/UnixCourse/fileAsst/TweedleDee/rabbit.dat

cd .. (this is to go back to the fileAsst directory)

The command below is executed as required:

~/cs252/bin/fileAsst-2

7 0
4 years ago
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