The area of a triangle is 16ft squared.<br><br> The height is 4 feet<br> What is the base?

Help plz i don’t understand this

sergij07 [2.7K]

The answer to your question is D

6 0

3 years ago

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Y=x-3<br> Slope intercept graph

Maksim231197 [3]

Answer:

hope that helps :)

8 0

3 years ago

Please help me lol a lil confused

alex41 [277]

$\leadsto f( \rm x) = - (x - 3)(x - 5)$

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$\leadsto f( \rm x) = - ( {x}^{2} - 5x - 3x + 15) \\$

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$\leadsto f( \rm x) = - ( {x}^{2} - 8x + 15) \\$

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$\leadsto f( \rm x) = - {x}^{2} + 8x - 15 \\$

3 0

2 years ago

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Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha

Nookie1986 [14]

Answer:

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ . The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ - Coefficients, dimensionless.

If we know that $(3, -30)$ , $(-2, 0)$ and $(18, 0)$ are part of the parabola, the following linear system of equations is formed:

$9\cdot a +3\cdot b + c = -30$

$4\cdot a -2\cdot b +c = 0$

$324\cdot a +18\cdot b + c = 0$

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

$a = \frac{2}{5}$ , $b = -\frac{32}{5}$ , $c = -\frac{72}{5}$ .