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vesna_86 [32]
3 years ago
12

Given that there were 4 Heads in the first 7 tosses, find the probability that the 2nd Heads occurred at the 4th toss. Give a nu

merical answer.
Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Answer:

The probability that the 2nd Heads occurred at the 4th toss is 5.99%.

Step-by-step explanation:

Given that there were 4 Heads in the first 7 tosses, to find the probability that the 2nd Heads occurred at the 4th toss the following calculation must be performed:

7 - 4 = 3

4/7 x 3/7 x 3/7 x 4/7 = X

0.571 x 0.428 x 0.428 x 0.571 = X

0.0599 = X

Therefore, the probability that the 2nd Heads occurred at the 4th toss is 5.99%.

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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