Tan(a/2) = sin a / (1 + cos a)
tan(45/2) = sin(45) / (1 + cos(45)) = (1/√2) / (1 + 1/√2) = (1/√2) / (√2 + 1)/√2 = 1/(√2 + 1) = (√2 - 1)
Answer:
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
Step-by-step explanation:
Given that,
A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.
From Pythagorean Theorem,
(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+
Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.
∴y²= x²+10²

Differentiating with respect to t


Since the car driving towards the intersection at 13 m/s.
so,

Now



= -12 m/s
Negative sign denotes the distance between the car and the person decrease.
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
Answer:
32 ft²
Step-by-step explanation:
Assuming the diagram attached below similar to the one required to complete the question below.
From the diagram,
Actaul Area of a parallelogram (A) = Actual Base(b)× actual heigth(h)
A = bh.......................... Equation 1
From the question,
If each 6 in on the scale drawing equals 3 feet
Given:
base on the scale drawing = 8 in.
Actual base(b) = (8×3)/6 = 4 feet.
Height on the scale drawing = 16 in
Actual height(h) = (16×3)/6 = 8 feet.
Substitute these values into equation 1
A = 4×8
A = 32 ft²
Hence the actual area of the shape is 32 ft²