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seraphim [82]
3 years ago
8

Paul makes 6 stacks of cans on a shelf in his kitchen he puts 2 cans in each stack witch eqaution and answer show the total numb

er of cans
Mathematics
1 answer:
likoan [24]3 years ago
8 0
6*2= 12 that should be right
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Andy's phone plan charges $0.45 per text messages plus $2.25 a day. Jeff's plan charges $0.20 a text plus an additional $3.50 a
Semenov [28]
Andy's y=.45+2.25x
Jeff's y=.2+3.5x
At 6 texts a day both the plans will be at $4.5.
Hope this helps.
8 0
4 years ago
A manufacturer receives parts from two suppliers. An SRS of 400 parts from supplier 1 finds 20 defective; an SRS of 100 parts fr
jeyben [28]

Answer:

Option C) 0.0602  

Step-by-step explanation:

We are given the following in the question:

x_1 = 20\\n_1 = 400\\x_2 = 10\\n_2 = 100

Let p1 and p2 be the proportion of all parts from suppliers 1 and 2, respectively, that are defective.

p_1 = \dfrac{x_1}{n_1} = \dfrac{20}{400} = 0.05\\\\p_2 = \dfrac{x_2}{n_2} = \dfrac{x_2}{n_2} = \dfrac{10}{100}= 0.1

First, we design the null and the alternate hypothesis

H_{0}: p_1 = p_2\\H_A: p_1 \neq p_2

We use Two-tailed z test to perform this hypothesis.

Formula:

\text{Pooled P} = \dfrac{x_1+x_2}{n_1+n_2}\\\\Q = 1 - P\\\\Z_{stat} = \dfrac{p_1-p_2}{\sqrt{PQ(\frac{1}{n_1} + \frac{1}{n_2})}}

Putting all the values, we get,

\text{Pooled P} = \dfrac{20+10}{400+100} = 0.06\\\\Q = 1 - 0.06 = 0.94\\\\Z_{stat} = \dfrac{0.05-0.1}{\sqrt{0.06\times 0.94(\frac{1}{400} + \frac{1}{100})}} = -1.883

Now, we calculate the p-value from the table at 0.05 significance level.

P-value = 0.0602

Thus, the correct answer is

Option C) 0.0602

7 0
4 years ago
NO LINKS!! Please help me with this problem​
vova2212 [387]

{\qquad\qquad\huge\underline{{\sf Answer}}}

The given vertex and Focus are of a vertical parabola having an opening downward as the focus is in downward direction as the vertex.

Focus of the parabola can be written as :

\qquad \sf  \dashrightarrow \: (h ,k+ a )

where, h and k are coordinates of vertex

so,

  • k + a = -2

  • -1 + a = -2

  • a = -1

So, the equation of parabola can be written as :

\qquad \sf  \dashrightarrow \: (x - h) {}^{2}  = 4a(y - k)

plug in the values ~

\qquad \sf  \dashrightarrow \: (x - 1) {}^{2}  =  4(- 1)(y  + 1) {}^{}

\qquad \sf  \dashrightarrow \: (x - 1) {}^{2}  =  - 4(y + 1)

6 0
2 years ago
Read 2 more answers
Explain why you can use subtraction to solve a division problem.
eduard
Subtraction is finding the difference between two numbers whereas division is putting numbers into equal pairs or undoing multiplication ( if that helps ) So... If they say divide 6 by 2 they mean put six into equal pairs of 2 which would equal 3 E.g.:- ( there are 3 pairs of six cars in twos ) You can't use subtraction because that will just find the number difference of 6 and 2 which is 4 Hope that wasn't complicated
7 0
3 years ago
PLEASE HELP
GaryK [48]

Answer:

he shortest distance from the point E to a side of square ABCD is 0.293

Step-by-step explanation:

The question parameters are

Shape of figure ABCD = Square

Point E lies on the diagonal line AC

The length of the segment AE = 1

Therefore, we have;

Length of AC = √(AB² + CD²) = √(1² + 1²) = √2

Hence, the point E is closer to the point C and the closest distance to a side   from E is the perpendicular from the point E to BC at point E' or to CD at poit E'' which is found as follows;

AC is a bisector of ∠DAB, hence;

∠DAC = 45° = ∠CAE'

EE' = EC × cos(45°)

EC = AC - AE = √2 - 1

Therefore;

EE' = (√2 - 1) × cos(45°) = (√2 - 1) × (√2)/2 = 1 - (√2)/2 = 0.293

Hence, the shortest distance from the point E to a side of square ABCD = 0.293.

7 0
3 years ago
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