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geniusboy [140]
3 years ago
6

The 3 points plotted below are on the graph of y=b^x. Based only on these 3 points, plot the 3 corresponding points that must be

on the graph of y=log_b x by clicking on the graph.

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

Step-by-step explanation:

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If y = 9 inches, z = 11 inches, h = 5 inches, and w = 4 inches, what is the area of the object?
Vesna [10]

Answer:

2

Step-by-step explanation:

because i am smart

5 0
3 years ago
What is x?<br><br> 3-2x=21<br><br> Show the steps?
JulsSmile [24]

Answer:

x = -9

Step-by-step explanation:

3-2x=21

-3       -3

-2x=18

/-2   /-2

x=-9

3 0
4 years ago
Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric
quester [9]
I'm guessing S^20 is actually referring to the 20th partial sum S_{20}, with

S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)

in the arithmetic case, and

S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}

in the geometric case.

(a) Combining like terms, we have

S_{20}=20+0.1(1+2+\cdots+18+19)

and invoking the formula

1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2

we end up with

S_{20}=20+0.1\dfrac{19\times20}2=39

(b) Multiply S_{20} by 1.1, then subtract this from S_{20}:

1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}

S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}
\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275
7 0
3 years ago
3x+-6+2 &gt; = 5x -8......can someone please solve this
Maksim231197 [3]

Answer:

x ≤ 2

Step-by-step explanation:

If you referencing ">=" as greater than or equal to, follow the solution below:

Solve:

3x - 6 + 2 ≥ 5x - 8

Combine like terms.

3x - 4 ≥ 5x - 8

Subtract 5x from both sides.

-2x - 4 ≥ -8

Add 4 to both sides.

-2x ≥ -4

Divide both sides by -2, while flipping the inequality as well since you're dividing by a negative number.

x ≤ 2

Your answer would be x ≤ 2

6 0
3 years ago
Can someone please click on my profile and answer my history question please!
ANEK [815]

Answer:

yeah sure

Step-by-step explanation:

3 0
3 years ago
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