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topjm [15]
3 years ago
12

How is friction involved in the movement of space​

Physics
2 answers:
pashok25 [27]3 years ago
7 0

Answer:

Friction can stop or slow down the motion of an object.

Explanation:

The slowing force of friction always acts in the direction opposite to the force causing the motion.

Mrrafil [7]3 years ago
6 0
What the other person said
You might be interested in
...............................................................help
chubhunter [2.5K]

Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²

hmax = 11481.77m - 5741.29m

hmax = 5740.48m

3 0
3 years ago
You are tossing pizza dough to get it ready to bake. If you toss the dough upward with a speed of 3.1 m/s, how high does it go?
ella [17]
0.49
hope it help Apex 







7 0
3 years ago
Read 2 more answers
a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un
AleksAgata [21]
1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to g=-10 m/s^2 (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
2gh=v_f^2-v_i^2
where h is the maximum height reached by the ball, v_i = 20 m/s is its initial velocity and v_f the velocity of the ball when it reaches the maximum height. But v_f=0 (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to  calculate h, the maximum height:
h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero: 
S(t)=0
where for an uniformly accelerated motion,
S(t)=v_i t +  \frac{1}{2} gt^2 =0
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s
where the negative sign means the ball is going downwards.
8 0
3 years ago
If an object weighs 300 N on earth, what is it’s mass on the moon?
inna [77]

Answer:

The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.

Explanation:

Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:

(weight) = (mass) x (gravitational acceleration)

We are to find the mass, knowing the weight on Earth to be 300N:

(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg

The mass of the object is 30.61kg.

The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.

If the question were what is its weight on the Moon, the answer would be

(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N

which is about 1/6 of the object's weight on the Earth.

4 0
3 years ago
How much money did congress authorize to be spent on its construction
ser-zykov [4K]

Answer:

20,000

Explanation:

5 0
4 years ago
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