The correct answer to the question is : 4000 N
EXPLANATION:
As per the question, the mass of the roller coaster is given as m = 2000 kg
The acceleration of the roller coaster is given as a = 2m/s2
We are asked to calculate the net force acting on the roller coaster.
From Newton's second laws of motion,we know that net external force acting on a particle is equal to the product of mass with acceleration of the particle.
Mathematically it is written as-
F = ma
Hence,net force acting on the roller coaster is calculated as-
F = 2000Kg×2m/s2
= 4000 N.
Here, Newton (N) is the unit of force.
Hence,net force acting on the roller coaster is 4000 N.
Complete Question
An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters ) is the airplane above the ground 13 seconds after takeoff?
Answer:
The height is 
Explanation:
From the question we are told that
The speed at which the plane takes off is 
The angle at which it takes off is 
The time taken is 
The vertical distance traveled is mathematically represented as
Substituting values
Answer:
Sun heating a car sitting in a parking lot
Explanation:
The sun heating a car sitting in a parking lot is an example of electromagnetic waves transferring energy.
- Electromagnetic waves are produced from the vibration between electric and magnetic fields.
- These waves can be propagated through vacuum with no particles inside of them.
- The sun produces electromagnetic radiation through the process of nuclear fusion.
- These radiations are used to warm the earth surface.
- The sun heating a car sitting a parking lot is one vivid example.
Average speed of the driver is given as
if he moved for total time t = 3.5 hours
so the distance between the tow is given as
so the distance between St. Louis and Chicago is 224 miles
Answer:
52 rad
Explanation:
Using
Ф = ω't +1/2αt²................... Equation 1
Where Ф = angular displacement of the object, t = time, ω' = initial angular velocity, α = angular acceleration.
Since the object states from rest, ω' = 0 rad/s.
Therefore,
Ф = 1/2αt²................ Equation 2
make α the subject of the equation
α = 2Ф/t².................. Equation 3
Given: Ф = 13 rad, t = 2.5 s
Substitute into equation 3
α = 2(13)/2.5²
α = 26/2.5
α = 4.16 rad/s².
using equation 2,
Ф = 1/2αt²
Given: t = 5 s, α = 4.16 rad/s²
Substitute into equation 2
Ф = 1/2(4.16)(5²)
Ф = 52 rad.
