LAN - Local area network :P
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
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</span>
Answer:
c) 4.4
Explanation:
You can evaluate step by step the code. You know tha your input is 4.0
Step 1 Variables definitions:
double tax;
double total;
Step 2 Ask the user for the input:
System.out.print("Enter the cost of the item");
Step 3 read de input:
total = scan.nextDouble();
Step 4 evaluate the condition ( is the input greater or equal than 3.0 ? [True])
if ( total >= 3.0)
Step 5 get done the operations inside the condition and print it:
tax = 0.10;
System.out.println(total + (total * tax));
Answer and Explanation:
In C programming language:
char fun(int*a, int*b){
printf("enter two integers: ");
scanf("%d%d",a,b);
int e;
printf("please enter a character: ");
e=getchar();
return e;
}
int main(int argc, char *argv[]) {
int d;
int f;
int g;
fun();
printf("%d%d%d", d, f, g);
}
We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.
