2 years ago

The radius of a circle measures 12 centimeters. What is the circumference of the circle?

Mathematics

1 answer:

Travka [436]2 years ago

8 0

Answer:

C=24π

Step-by-step explanation:

C=2πr

C=2π12

C=24π

≈75.39

You might be interested in

4. Amachine can make 88 pens in an 8 minute time pened How many pens cani make in a minute time period Answer

Bad White [126]

11 pens per minute .

5 0

2 years ago

Read 2 more answers

The total cost of a $70.42 meal after a 20% tip<br> $

egoroff_w [7]

Answer:

$84.50

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What digit in the serial number of this dollar bill occurs most often? 6,8,5,8,2,8,5,8

Nastasia [14]

8 occurs most often.

7 0

3 years ago

Given that a randomly chosen quadrilateral has four right

xeze [42]

Answer:

it think this question is 25%

8 0

2 years ago

Read 2 more answers

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

2 years ago