Answer:
the average rate of change rc is 13 , 12.1 and 12.01 for h=1 , 0.1 and 0.01 respectively
Step-by-step explanation:
for
R(t) = 30*t − 3*t² ; t = 3
the average rate of change of R(t) over the time interval [t, t + h] is
rc= [R(t+h)-R(t)] / [(t+h) -t) = [R(t+h)-R(t)] /h = 1/h * [ 30*(t+h) − 3*(t+h)² - ( 30*t − 3*t² ) ] = (1/h) * ( 30*h - (3*t² + 6*t*h + t²) +3*t² ) = 30 - 6*t + h
then
rc= 30 - 6*t + h
for t=3 and h=1
rc= 30 - 6*3 + 1 = 13
for t=3 and h=0.1
rc= 30 - 6*3 + 0.1 = 12.1
for t=3 and h=0.01
rc= 30 - 6*3 + 0.01 = 12.01
for t=3 and h=0.001
rc= 30 - 6*3 + 0.01 = 12.001
when h goes smaller , the average rate of change gets closer to the instantaneous rate of change of R(t) in t=3 (the derivative of R in t=3) , that is
R'(t)= 30 - 6*t
Step-by-step explanation:
Many factors would be used to assess the effectiveness of a human rights campaign, including the following:
Social Influence. Direct Interpersonal Reach. Participant Observation. Reputation. Volume of Search & Interest. Website Traffic.
National Research.
divide the fraction like 4/5 and I'll give you decimal form and you could tell which one was bigger very quickly
To solve this problem, what we have to do is to calculate
for the z scores of each condition then find the probability using the standard
normal probability tables for z.
The formula for z score is:
z = (x – u) / s
where,
x = sample value
u = sample mean = 23 days
s = standard deviation = 1 day
A. P when x < 21 days
z = (21 – 23) / 1
z = -2
Using the table,
P = 0.0228
Therefore there is a 2.28% probability that the hatching
period is less than 21 days.
B. P when 23 ≥ x ≥ 22
<span>z (x=22) = (22 – 23) / 1 = -1</span>
P (z=-1) = 0.1587
z (x=23) = (23 – 23) / 1 = 0
P (z=0) = 0.5
P = 0.5 - 0.1587 = 0.3413
Therefore there is a 34.13% probability that the hatching
period is between 22 and 23 days.
C. P when x > 25
z = (25 – 23) / 1
z = 2
P = 0.9772
This is not yet the answer since this probability refers
to the left of z. Therefore the correct probability is:
P true = 1 – 0.9772
P true = 0.0228
<span>Therefore there is a 2.28% probability that the hatching
period is more than 25 days.</span>
I guess it wiil be solved like this
