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2 years ago

Jasmine wants to earn $2,000 in simple interest through a

Mathematics

1 answer:

Ierofanga [76]2 years ago

3 0

Answer:

$10000

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

P = 2000 / ( 0.05 × 4 ) = 10000

P = $ 10,000.00

The principal required to

accumulate interest of $ 2,000.00

on a rate of 5% per year for 4 years is $ 10,000.00.

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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and

strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

X ~ N ( u , s /√n )

Where

s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )

= P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1

7 0

3 years ago

Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

bekas [8.4K]

Answer:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

$p(A) = \frac{5}{7}$

$p(B) = \frac{2}{3}$

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

And for this special case we want to find this probability:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

7 0

3 years ago

Given f(x)=x-7/3 solve for f^-1(4)

GrogVix [38]

I hope this hepls you

f⁻¹(x)=3x+7

f⁻¹(4)=3.4+7=19

8 0

3 years ago

The cost of 2 plates of spaghetti & 1 plate of salad is $27.50. The cost for 4 plates of spaghetti & 3 salads is $59.50.

k0ka [10]

2a+1b=27.50

4a+2b=59.50

Multiply first equation by -4 and the second by 2 so you can drop off the a values then add the equations together. Then solve for b. You should get b=6.

Then plug b into one of the original equations and solve for a and you should get 10.75

So a plate of spaghetti is $10.75 and a salad is $6.

<em><u>Please mark brainliest!</u></em>

8 0

3 years ago

9 + (-8) using a number line

Lelu [443]

Answer:

9 + (-8) = 1

Step-by-step explanation:

4 0

2 years ago