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seropon [69]
3 years ago
12

A sweater is on sale for $33. This is 75% of the original price. Find the original price?

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0
75% of the original price is $33.

33 = 75% * x

33 = 75/100 * x

33 = 3/4 * x

x = 33 * 4/3

x = 11 * 4

x = 44


The original price of the sweater was $44.
kap26 [50]3 years ago
6 0
It was $44
I just plugged in numbers I did 44*0.75 and it gave me 33.
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Answer:

14,000+2.1%(0.021)x

Step-by-step explanation:

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Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

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2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

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7 0
3 years ago
A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula
kvasek [131]

Answer:

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\hat{p}=\frac{25}{70}=0.3571

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

Where:

z_{\frac{0.05}{2}}=1.96 is the critical value at 0.05 significance level

\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }

         0.3571 \pm 0.1122

         \left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)

         \left(0.245,0.469 \right)

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)



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