Answer:
-2r-19p
Step-by-step explanation:
-4p-2r-15p
add like terms
-2r-19p
Answer:
the correct answer is 5 bags
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
9514 1404 393
Answer:
x = 33
Step-by-step explanation:
The angles are complementary.
x° = 90° -57°
x = 33
Answer:
{2, 4}
Step-by-step explanation:
Intersection is the elements that two or more sets have in common. In A and B, they share {2, 4} in common.
