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Free_Kalibri [48]
3 years ago
7

If two angles are complementary each angle is called a complement of the other if two angles are supplementary each angle is cal

led a supplement of the other
1. Suppose m∠A = 77° what is the measure of a complement of a complement of ∠A? Explain

2. what conclusion can you draw about a complement of a complement of an angle? explain
Mathematics
2 answers:
professor190 [17]3 years ago
8 0
Remember that complementary angles add to 90 degrees.

so therefor, you can find the complement of m<A by solving 

90 - 77 = A

A = 13 degrees

^^^ This explains the second part.

The compliment of a compliment can be found by subtracting the known compliment from 90 :) 
aleksklad [387]3 years ago
4 0

Answer:

1) Complement = 90 - 77 = 13⁰

2) We can conclude that complement of complement of any angle is the angle itself

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Evaluate the integral by making an appropriate change of variables.
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<em>u</em> = <em>y</em> + <em>x</em>

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<em />

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in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

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<em />

So, the integral becomes

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=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

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2 years ago
What situation could this represent?<br><br>NEED HELP ASAP PLEASE ​
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Answer:

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