3×the fraction blank 3 =1
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Three of the four towns are on the vertices of the triangle ΔCBD, through
which the bearing can calculated.
<h3>Response:</h3>- The bearing of D from B is approximately <u>209.05°</u>
From the given information, we have;
AC = AB = 25 km
∠BAC = 90° (definition of angle between north and east)
ΔABC = An isosceles right triangle (definition)
∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)
The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the
direction of <em>D.</em>
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Therefore;
- The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>
Learn more about bearings in mathematics here:
