Answer:
102 mg
Step-by-step explanation:
Let's convert 28 pounds to kgs.
Since 1 kg = 2.2 pounds, we can find:
So 28 pounds is 12.73 Kg
Since 8mg is given per kg, for 12.73 kg, the amount given should be:
12.73 * 8 = 101.84
Rounded to nearest whole number, that is, 102 mg
The area of the square pyramid building is the amount of space on it
The maximum base length of the building is 67.42 cm
<h3>How to determine the maximum side length?</h3>
The given parameters are:
Base = b
Slant height (l) = 5b
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * b * 5b
Evaluate the product
L = 10b^2
The total surface area is calculated using:
T = L + b^2
So, we have:
T = 10b^2 + b^2
Evaluate the sum
T = 11b^2
The maximum surface area is 50,000 square feet
So, we have:
11b^2 = 50000
Divide both sides by 11
b^2 = 50000/11
Take the square root of both sides
b = 67.42
Hence, the maximum base length of the building is 67.42 cm
Read more about square pyramids at:
brainly.com/question/27226486
Answer:
1/7
Step-by-step explanation:
Given that:
Using a scale factor of 7 ; the dimension of a rectangle is : 2 inches by 3 inches
In other to obtain the original size of the rectangle, all that is needed is to multiply the sacl d dimension by the reciprocal of the initi. Scale factor used, that is 1 / 7
This gives :
(2 inches by 3 inches) * 1/7
2/7 inches by 3/7 inches
Hence, required scale factor is 1/ 7
Answer:
- the given dimension was used as the radius
- 5.57 m³
Step-by-step explanation:
The volume of a sphere can be found using the formula ...
V = 4/3πr³ . . . . . where r is the radius
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The figure points to a diameter line and indicates 2.2 m. The arrowhead is in the middle of a radius line, making it easy to interpret the dimension as the radius of the sphere.
If 2.2 m is used as the radius, the volume is computed to be ...
V = 4/3π(2.2 m)³ ≈ 44.58 m³
This agrees with your friend's volume, suggesting the diameter was used in place of the radius in the computation.
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The correct volume, using 2.2 m as the diameter, is ...
V = 4/3π(1.1 m)³ ≈ 5.57 m³
