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Virty [35]
3 years ago
12

A manufacturer of matches randomly and independently puts 24 matches in each box of matches produced. The company knows that one

-tenth of 5 percent of the matches are flawed. What is the probability that a matchbox will have one or fewer matches with a flaw?
Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

There is a 0.36% Chance of 1 or fewer in every 24 matches being flawed.

Step-by-step explanation:

Firstly we need to know what 1/10 of 5 is. It is 0.5.

You then need to multiply 24 by 1.5 to get 36. We then need to  divide that by 100 to get a percentage and we end up with 0.36%

Here is an explanation of how to get percentages: https://www.mathsisfun.com/converting-fractions-percents.html

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What is the coefficient in the following expression <br><br>5+3x+ (-3)​
polet [3.4K]

Answer:

The coefficient is 3.

Step-by-step explanation:

The coefficient is the number that is grouped with an unknown number represented by a letter.

7 0
3 years ago
Evaluate the exponential expression (−2)6. Question 6 options: −12 12 −64 64
OlgaM077 [116]

Answer:

64

Step-by-step explanation:

(-2) ^6

This is -2 multiplied by itself 6 times

-2 * -2 *-2 * -2* -2 *-2

64

7 0
4 years ago
What is 1,250 rounded to the nearest whole number?
mariarad [96]

Answer:1,200

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(Recall, to solve |u| = c, one must solve u = c and u = −c.)<br> Solve: |3x-1| +2=8
11Alexandr11 [23.1K]

Answer:

The answer is 5/3, 1 2/3, and 1.67

Step-by-step explanation:

The answer to this problem is simple as everything between the two lines will come out to be a positive. So the equation will end up coming out to be 3x+1+2=8.

Now we add the 1 and 2....

3x+3=8

To make this problems simple we can subtract the 3 from the left side and do the same on the right side making the equation say...

3x=5

Now we can make it easier to solve but it will not be a whole number. We now divide 3 from the left and right side leaving us with....

x = 5/3

So this answer could be 5/3 , 1 2/3, and 1.67

4 0
1 year ago
State the composition of transformations used below that take △ABC to △ A" B" C" .
kupik [55]

We have to identify the transformations that take △ABC to △A"B"C".

The first transformation takes △ABC to △A'B'C'. We can see that the triangle is reflected over the x-axis (horizontal axis).

For example, as C is located on the x-axis, C' is also located on the x-axis. For A and B, its vertical coordinates change sign but mantain its absolute value.

We can write this transformation as:

(x,y)\longrightarrow(x,-y)

This transformation shows that the horizontal coordinates are mantained and the vertical coordinates have their sign inverted.

The second transformation is a translation. The orientation stays the same but the points are translated a fixed number of units in both the horizontal and vertical direction.

We can take any point and its transformed point and compare its coordinates. For example B'' is 6 units to the right and 2 units up.

Then, we can write:

B(-1,2)\longrightarrow B^{\prime}^{\prime}(5,4)

We can generalize this to the rule:

(x,y)\longrightarrow(x+6,y+2)

as the x-coordinate will increase 6 units and the y-coordinate will increase 2 units.

Answer: the transformations are a reflection over the horizontal axis (y=0) and a translation of (x+6,y+2) [First option].

​

3 0
1 year ago
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