you could chose to describe the first graph as any of the following phrases:
‘curved graph’
‘intercept on y-axis’
‘as x increases, y increases’,
‘y increases slowly at first, then more rapidly, then slows down again’ and ‘reaches a maximum level’.
you can chose to describe the second graph as any of the following phrases:
'gradually increases, then rapidly increases in a short period of time"
All organisms are made of cells
all existing cells are produced by other living cells
the cell is the most basic unit of life
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
