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densk [106]
3 years ago
7

The overhead reach distances of adult females are normally distributed with a mean of 202.5 and standard deviation of 8 cm. a. F

ind the probability that an individual distance is greater than 215.90 cm. b. Find the probability that the mean for 20 randomly selected distances is greater than 201.20 cm. c. Why can the normal distribution be used in part (b)even though the sample size does not exceed 30?
Mathematics
1 answer:
Lorico [155]3 years ago
4 0

Answer:

HSDHJSDHJS

Step-by-step explanation:

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nika2105 [10]

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90 degrees

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What is the solution to the quadratic equation 8m^2+7m-15=-7 ?
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add7 both sides
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quadratic fomrula

if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

8m^2+7m-8=0
a=8
b=7
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x=\frac{-7+/- \sqrt{7^{2}-4(8)(-8)} }{2(8)}
x=\frac{-7+/- \sqrt{49+256} }{16}
x=\frac{-7+/- \sqrt{305} }{16}

x=\frac{-7+ \sqrt{305} }{16} or x=\frac{-7- \sqrt{305} }{16}

aprox
x=-1.52902 or 0.654016


4 0
2 years ago
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