The area of a triangle is represented by 1/2 x B x H, where B = base, H = height.
In this equation, B = 4, H = 6
1/2 x 4 x 6 = 12 in^2
Answer:
y=x\\
x=y^{2} + 12y\\
y^{2} + 12y -x = 0\\
Delta = (12^{2}) - 4.1.(-x) = 144 +4X = 36.(4+x)
\sqrt{Delta} = 6 . \sqrt{(4+x)} \\
y' = \frac{-12 + 6.(\sqrt{(4+x)}}{2} = -6 + 3.\sqrt{(4+x)}\\
y" = -6 - 3.\sqrt{(4+x)}\\\\
y' = 3.\sqrt{(4+x)} - 6\\
y''= -3.\sqrt{(4+x)} - 6\\
So what we want to know is how long is the car that is 6% shorter then the other car. We can look at it this way: the shorter car is 94% the lenght of the longer car. Lets call the length of the shorter car x, then we have the equation: 94% * 3.9m=x. Or, (94/100)*3.9=x. Now we solve for x and get: x= 3.666m. So the shorter car is 3.666 m long.
Answer:
10
Step-by-step explanation:
Answer:
. B. If the distribution of the sample means is normally distributed, and greater than30, then the population distribution is normally distributed
