3 years ago

Find three equivalent ratios to 12:18

Mathematics

1 answer:

Scilla [17]3 years ago

7 0

Answer:

6:3, 2:1, 4:2

If you need more explanation, let me know.

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Please answer it correctly and please show work please help me if it’s correct I will mark you brainliest

Eva8 [605]

Answer:

210 hours

Step-by-step explanation:

Step 1: Make an expression

(2/3 * 1575) / 5

Step 2: Multiply

(2/3 * 1575)/5

(1050) / 5

Step 3: Divide

(1050) / 5

210 hours

Answer: 210 hours

8 0

2 years ago

How can I get to 75 using 7 5 6 3

eduard

63+5+7=75

Hope this helps

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2 years ago

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The equation below is a horizontal line. y = −4 true? or false?

777dan777 [17]

Answer:

That is true. If you graph y=-4 it would be a horizontal line on the y axis

Step-by-step explanation:

5 0

3 years ago

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Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x

Triss [41]

Answer:

$\frac{1}{ 2\sqrt{7} }$

Step-by-step explanation:

$\lim_{x\to 0} \frac{ \sqrt{x + 7} - \sqrt{7} }{x} \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} - \sqrt{7}) }{x} \times \frac{( \sqrt{x + 7} + \sqrt{7}) }{( \sqrt{x + 7} + \sqrt{7}) } \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} )^{2} - (\sqrt{7})^{2} }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{( {x + 7} - {7}) }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {1}}{\sqrt{x + 7} + \sqrt{7}} \\ \\ = \frac{1}{ \sqrt{0 + 7} + \sqrt{7} } \\ \\ = \frac{1}{ \sqrt{7} + \sqrt{7} } \\ \\ = \frac{1}{ 2\sqrt{7} }$

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3 years ago

Solve the following system of equations using matrices: 4x + 5y = 40 X-y=1

Sergeeva-Olga [200]

I think i’m not sure but i think the answer is (5,4) x=5 and y=4

4 0

2 years ago