The width of a piece of paper was 1/2. The area of the paper was 9/16. What was the length of the paper

Irene knows there are 2 cups in 1 pint. She writes the equation c=2p to find the number of cups, c, in any number of pints, p. U

Natasha2012 [34]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as there are no options to select from.

However, a general explanation is as follows.

Given

$2\ cups = 1\ pint$

Required

Is $c = 2p$ a correct expression?

Let

$c = cups$

$p = pint$

So:

$2\ cups = 1\ pint$

becomes

$2 * c = 1 * p$

$2c = p$

Divide both sides by 2

$c =\frac{1}{2}p$

Hence:

$c = 2p$ is incorrect

4 0

2 years ago

Determine the value of x and y and the following diagram

Tatiana [17]

Answer:

Step-by-step explanation:

first subtract 125-180=X you will get X=55 so then add X+X+y=180 which x+x+y= is actually 55+55+y=180 but don't add the y just yet add 55+55 then you will get 110+y=180 so then flip it backwards and do y=180-110 and your anwser is y=70

7 0

2 years ago

Read 2 more answers

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

Which number(s) below belong to the solution set of the inequality? Check all that apply.x + 16 < 51.

natta225 [31]

If you subtract 16 on both sides... x will be alone. Therefore 51-16=35
x=35 (B)

5 0

2 years ago

State which of the following ordered pairs is a function. Set A: (-1, 0), (-2, 1), (4, 3), (3, 4) Set B: (1, 4), (2, 3), (3, 2),

Mice21 [21]

Answer:

Both set A and B.

Step-by-step explanation:

Set A: (-1, 0), (-2, 1), (4, 3), (3, 4)

Set B: (1, 4), (2, 3), (3, 2), (4, 1)

Set C: (2, 1), (3, 2), (2, 3), (1, 4)

In order for (x,y) to be a function, only one x get the value of y, but many x'es can get the value y.

Looking at the set A and B, and the definition above, we can say that they are functions.

What about set C? It is not a function, as x = 2 is equal 1 or 3, which does not meet the condition from the definition.

6 0

3 years ago